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### CAMB: Initial condition phidot

Posted: December 20 2005
Hi,

I'm trying to run CAMB with the Quintessence module but with a constant phidot unequal to zero.and I'm a total greenhorn when it comes to programming in Fortran90. The potential I want to use ist $$V(\phi) = V0 / (d * sinh(B * \phi) + cosh(B * \phi) - 1)^2$$. It runs wonderfully with phidot=0, that's not the model I want.

Can someone help me with that fast?

Thanks,

Christine

### Re: CAMB: Initial condition phidot

Posted: December 20 2005
You can change the initial conditions in the code - search for phidot in the source.

Incidentally, the non-public quintessence module currently doesn't describe the normalization of V accurately: the output of the Vofphi routine should be in 1/Mpc^2 units. In other words if V is 10^{-122} in natural units, Vofphi should be returning
$$10^{-122}(Mpc/c)^2 /T_{pl}^2 .$$

### CAMB: Initial condition phidot

Posted: December 21 2005
Hi!

Sorry for this stupid question, but what is $$T^2_{pl}$$??

Christine

(A bit desperate due to presure of time;-)

### Re: CAMB: Initial condition phidot

Posted: December 21 2005
Planck time squared.