## CAMB: Initial condition phidot

Use of Healpix, camb, CLASS, cosmomc, compilers, etc.
Christine Fix
Posts: 2
Joined: December 20 2005
Affiliation: University of Ulm

### CAMB: Initial condition phidot

Hi,

I'm trying to run CAMB with the Quintessence module but with a constant phidot unequal to zero.and I'm a total greenhorn when it comes to programming in Fortran90. The potential I want to use ist $V(\phi) = V0 / (d * sinh(B * \phi) + cosh(B * \phi) - 1)^2$. It runs wonderfully with phidot=0, that's not the model I want.

Can someone help me with that fast?

Thanks,

Christine

Antony Lewis
Posts: 1522
Joined: September 23 2004
Affiliation: University of Sussex
Contact:

### Re: CAMB: Initial condition phidot

You can change the initial conditions in the code - search for phidot in the source.

Incidentally, the non-public quintessence module currently doesn't describe the normalization of V accurately: the output of the Vofphi routine should be in 1/Mpc^2 units. In other words if V is 10^{-122} in natural units, Vofphi should be returning
$10^{-122}(Mpc/c)^2 /T_{pl}^2 .$

Christine Fix
Posts: 2
Joined: December 20 2005
Affiliation: University of Ulm

### CAMB: Initial condition phidot

Hi!

Sorry for this stupid question, but what is $T^2_{pl}$??

Christine

(A bit desperate due to presure of time;-)

Antony Lewis
Posts: 1522
Joined: September 23 2004
Affiliation: University of Sussex
Contact:

### Re: CAMB: Initial condition phidot

Planck time squared.