When using Planck 2018 data to find the bestfit point of my model (I used the lowl-likelihoods, lowl EE & TT+TE+EE), I got this:
-log(Like) chi-sq data
11.136 22.272 CMB: lowl = commander_dx12_v3_2_29
198.227 396.455 CMB: simall = simall_100x143_offlike5_EE_Aplanck_B
1173.849 2347.699 CMB: plik = plik_rd12_HM_v22b_TTTEEE
It might be a very silly question, but what are the degrees of freedom of each one of this datasets?
I found a similar question in the forum (viewtopic.php?f=11&t=2251&p=7283&hilit=degrees#p7283), but I could not get the answer.
Number of degrees of freedom in Planck 2018 data
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