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Temperature Anisotropies !

Posted: March 28 2017
by Muhammad Junaid
Hi everyone,

I just have one simple question question, I want to calculate the temperature anisotropies as a function of wave number i.e. [tex]\Delta T(k)/T[/tex] using the list of transfer functions output from the camb code. I just want to use my own initial power spectrum [tex]P_\zeta(k)[/tex] of initial perturbations(comoving curvature perturbations) to calculate [tex]\langle \Delta T^2(k)/T^2 \rangle = \Delta_i^2(k) P_\zeta(k)[/tex]. Where [tex]\Delta_i(k)[/tex] would be some combination of transfer functions of the camb code. So, what precise combinations of transfer functions do I need here as [tex]\Delta_i[/tex]'s?

Thanks in Advance!!

M Junaid

Re: Temperature Anisotropies !

Posted: March 28 2017
by Antony Lewis
Are you sure you don't want to calculate the C_\ell power spectrum? That's easily done by modifying CAMB's power_tilt.f90 to use your own initial power spectrum (and increasing accuracy settings if needed).

Temperature Anisotropies !

Posted: March 28 2017
by Muhammad Junaid
No we are working out some moments in momentum space so we don't need [tex]C_l[/tex] or any angular part.

Temperature Anisotropies !

Posted: March 30 2017
by Muhammad Junaid
My hunch is that the temperature anisotropy is to leading order equal to [tex] \Delta T/T \approx \frac{1}{4} \hat{\Delta}_\gamma+ 2\Phi[/tex], where [tex]\Phi[/tex] is Weyl potential. While, you have said in your notes that power spectrum of Weyl potential is [tex]P_\Phi=T_\Phi(k) P_\zeta(k)[/tex] where [tex]\zeta[/tex] is primordial perturbations. Is the same true for other power spectra as [tex]\Delta_\gamma^2 = \hat{\Delta}_\gamma^2 P_\zeta(k)[/tex]. So the transfer function output from the camb code are [tex]\hat{\Delta}_\gamma^2[/tex] that don't include the primordial power spectrum [tex]P_\zeta(k)[/tex]. Please correct me if I am wrong!

M.

Re: Temperature Anisotropies !

Posted: March 30 2017
by Antony Lewis
Transfer function outputs are not squared (and indeed not scaled by the primordial power). The temperature sources are quite complicated in general (calculated in output routine of equations.f90).