Hi Antony,
I have a very simple question, but I want to be sure. You define dgpi in /camb/equations.f90 as
[tex]\text{dgpi} = \sum 8 \pi G a^2 \rho_i \Pi_i[/tex]
So, in Newtonian gauge, I should write the Einstein equation as
[tex]k^2 (\phi  \psi) = 12 \pi G a^2 \sum (\rho + P )\sigma = \frac{3}{2} \text{dgpi}[/tex].
Am I wrong?
Thanks,
Alex
Definition of dgpi (/camb/equations.f90)

 Posts: 4
 Joined: June 24 2015
 Affiliation: Simon Fraser University

 Posts: 1636
 Joined: September 23 2004
 Affiliation: University of Sussex
 Contact:
Re: Definition of dgpi (/camb/equations.f90)
Not sure about the factor of 3/2, e.g. see the second equation on p12 of the CAMB notes.

 Posts: 4
 Joined: June 24 2015
 Affiliation: Simon Fraser University
Definition of dgpi (/camb/equations.f90)
Great, thanks!
Alex
Alex