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YinZhe Ma
Joined: 09 Oct 2008 Posts: 4 Affiliation: University of British Columbia
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Posted: December 02 2011 |
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Hi Guys,
I don't quite understand the meaning of drag epoch. In Komatsu 2009 paper, it says:
the drag epoch zd and the decoupling epoch z*:
They would be equal only when the energy density of photons and that of baryons were equal at the decoupling epoch – more precisely, they would be equal only when R=3ρb/4ργ=1 at z=z*?
What does this mean?
And why does the low density of baryon leads to later of drag epoch?
Thank you! |
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Ben Gold
Joined: 25 Sep 2004 Posts: 97 Affiliation: University of Minnesota
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Posted: December 07 2011 |
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The decoupling epoch is when the photon optical depth is one.
The drag epoch is when the baryon optical depth is one.
Since there are many more photons than baryons, the photons "decouple" (stop noticing the baryons) before the baryons stop noticing the photons. |
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